A `30 kg` projectile moving horizontally with a velocity `vecv_(0)=(120m//s)hati` explodes into two fragments `A` and `B` of masses `12 kg` and `8 kg`, respectively. Taking point of explosion as origin and knowing that `3s` later position of fragment a is (`300m, 24m, -48m`), determine the position of fragment `B` at the instant.

Explanation

To solve the problem, we need to find the position of fragment B after the explosion, given the position of fragment A and the initial conditions of the projectile.

### Step-by-Step Solution:

1. **Understanding the System**:
The projectile has a mass of 30 kg and is moving horizontally with a velocity of \( \vec{v_0} = 120 \, \text{m/s} \hat{i} \). After the explosion, it breaks into two fragments: A (12 kg) and B (8 kg).

2. **Position of Fragment A**:
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