A `3.00 kg` steel hall strikes the wall with a speed of `10.0 m//s` at an angle of `60^(@)` with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for `0.200 s`, what is the average force exerted by the wall on the ball?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the components of velocity
The ball strikes the wall at an angle of \(60^\circ\) with the surface at a speed of \(10.0 \, \text{m/s}\). We need to resolve this velocity into two components:
- **Perpendicular to the wall**: \(V_{\perp} = V \sin(60^\circ)\)
- **Parallel to the wall**: \(V_{\parallel} = V \cos(60^\circ)\)

### Step 2: Calculate the components
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