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A ball strikes a smooth horizontal floor...

A ball strikes a smooth horizontal floor obliquely and rebounds inelastically.

A

The kinetic energy of the ball just after hitting the floor is equal to the potential energy of the ball at its maximum height alter rebound.

B

Total energy of the ball is not conserved.

C

The angle of rebound with the vertical is greater than the angle of incidence.

D

None of the above.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of a ball striking a smooth horizontal floor obliquely and rebounding inelastically, we will analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding the Collision**: - The ball strikes the floor at an angle, which means it has both horizontal and vertical components of velocity. - The collision is inelastic, meaning that the ball does not retain all of its kinetic energy after the collision. 2. **Coefficient of Restitution**: - The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation to the relative velocity of approach. - Since the collision is inelastic, the coefficient of restitution will be between 0 and 1 (0 < e < 1). 3. **Kinetic Energy Before and After Collision**: - Before the collision, the kinetic energy (KE) of the ball can be expressed as: \[ KE_{initial} = \frac{1}{2} m u^2 \] - After the collision, the kinetic energy will be: \[ KE_{final} = \frac{1}{2} m v^2 \] - Due to the inelastic nature of the collision, some kinetic energy is transformed into other forms of energy (like sound, heat, etc.), so: \[ KE_{final} < KE_{initial} \] 4. **Potential Energy at Maximum Height**: - After rebounding, the ball will rise to a maximum height where its kinetic energy is converted into potential energy (PE). The potential energy at the maximum height (h) is given by: \[ PE = mgh \] - Since some kinetic energy is lost during the collision, the kinetic energy just after hitting the floor will not equal the potential energy at the maximum height. 5. **Conservation of Energy**: - The total mechanical energy of the ball (kinetic + potential) is not conserved in this case because some energy is lost during the inelastic collision. Therefore, the statement that the total energy of the ball is conserved is incorrect. 6. **Angles of Incidence and Rebound**: - The angle of incidence (α) is the angle at which the ball strikes the floor, and the angle of rebound (β) is the angle at which it leaves the floor. - In an inelastic collision, the angle of rebound is typically greater than the angle of incidence due to the loss of energy and the change in momentum direction. ### Conclusion: Based on the analysis: - **Option A** is incorrect because the kinetic energy just after hitting the floor is not equal to the potential energy at the maximum height after rebound. - **Option B** is correct because the total energy of the ball is not conserved during the inelastic collision. - **Option C** is correct because the angle of rebound is greater than the angle of incidence in an inelastic collision. - **Option D** is incorrect as there are correct options (B and C). ### Final Answer: The correct options are **B** and **C**. ---

To solve the problem of a ball striking a smooth horizontal floor obliquely and rebounding inelastically, we will analyze the situation step by step. ### Step-by-Step Solution: 1. **Understanding the Collision**: - The ball strikes the floor at an angle, which means it has both horizontal and vertical components of velocity. - The collision is inelastic, meaning that the ball does not retain all of its kinetic energy after the collision. ...
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