A ball of mass `1 kg` is dropped from a height of `3.2 m` on smooth inclined plane. The coefficient of restitution for the collision is `e= 1//2`. The ball's velocity become horizontal after the collision.

Options

A. the angle `theta=tan^(-1)(1/sqrt2)`
B. The speed of the ball after the collision `=4sqrt2ms^(-1)`
C. The total loss in kinetic energy during the collision is `8 J`.
D. The ball hits the inclined plane again while travelling vertically downward.

Answer

A, B

Explanation

`8sintheta=vcostheta`
`(8costheta)/2=vsintheta`
`implies tantheta=1/sqrt(2)`
`v=8/sqrt(2)=3sqrt(2)ms^(-1)`
`/_\k=1/2xx1[(4sqrt2)^(2)-8^(2)]=-16J`