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A particle A suffers an oblique elastic ...

A particle A suffers an oblique elastic collision particle `B` that is at rest initially. If their masses with a are the same, then after the collision

A

their `KE` may be equal

B

A continues to move in the original direction while `B` remains at rest

C

they will move in mutually perpendicular directions

D

A comes to rest and `B` starts rections moving in the direction of the original motion of `A2`

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To solve the problem of an oblique elastic collision between two particles A and B, we will follow these steps: ### Step-by-Step Solution: 1. **Understand the Scenario**: - Particle A is moving with an initial velocity \( u \) and collides with particle B, which is initially at rest. Both particles have the same mass \( m \). 2. **Conservation of Momentum**: - The principle of conservation of momentum states that the total momentum before the collision is equal to the total momentum after the collision. - The equation can be written as: \[ m \cdot u + m \cdot 0 = m \cdot v_1 + m \cdot v_2 \] - Simplifying this gives: \[ mu = mv_1 + mv_2 \] - Dividing through by \( m \) (since \( m \neq 0 \)): \[ u = v_1 + v_2 \quad \text{(Equation 1)} \] 3. **Elastic Collision Condition**: - In an elastic collision, the coefficient of restitution \( E \) is defined as the ratio of the relative velocity of separation to the relative velocity of approach. - For this case, since \( E = 1 \): \[ E = \frac{v_2 - v_1}{u} = 1 \] - Rearranging gives: \[ v_2 - v_1 = u \quad \text{(Equation 2)} \] 4. **Solving the Equations**: - Now we have two equations: 1. \( v_1 + v_2 = u \) 2. \( v_2 - v_1 = u \) - Adding these two equations: \[ (v_1 + v_2) + (v_2 - v_1) = u + u \] \[ 2v_2 = 2u \implies v_2 = u \] - Substituting \( v_2 = u \) back into Equation 1: \[ v_1 + u = u \implies v_1 = 0 \] 5. **Conclusion**: - After the collision, particle A comes to rest (\( v_1 = 0 \)), and particle B moves with the velocity of particle A (\( v_2 = u \)). Therefore, particle B moves in the same direction as particle A was initially moving. ### Final Answer: - Particle A comes to rest, and particle B moves in the direction of the original motion of particle A.

To solve the problem of an oblique elastic collision between two particles A and B, we will follow these steps: ### Step-by-Step Solution: 1. **Understand the Scenario**: - Particle A is moving with an initial velocity \( u \) and collides with particle B, which is initially at rest. Both particles have the same mass \( m \). 2. **Conservation of Momentum**: ...
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