Figure shows position and velocities of two particles moving under mutual gravitational attraction in space at time `t = 0`. The position of centre of mass after one second is
`'"*"'m`. Fill `"'*"'`.

Answer

8

Explanation

As `vecF_(ext)=0,veca_(cm)=0`
`vecV_(cm)=(2xx8hati-3xx2hati)/(2+3)=2hati`
`x_(cm)=(2xx3+3xx8)/(2+3)=6m`
As `vecV_(cm) ` is constant
Therefore `CM` will move `2m` in `1 s`.
`:.6+2=8m`