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A ball of mass m is allowed to roll down...

A ball of mass `m` is allowed to roll down the wedge of mass `M = 2m` as shown in the figure. What is the displacement of wedge (in `m`) when the ball reaches from `A` to `B`? Take `theta=45^(@), h=1m, d=4m`

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The correct Answer is:
2
Displacement of wedge
`/_\x_("wedge")=(m(2hcottheta+d))/((M+m))` towards left
`(m/(2m+m))(4+2xx1xx1)=1/3(6)=2m`
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