The magnitude of the force (in newtons) acting on a body varies with time t (in micro seconds) as shown in the fig AB, BC and CD are straight line segments. The magnitude of the total impulse of the force on the body from `t= 4 mus` to `t=16 mus` is ….Ns

Answer

NA

Explanation

We know that area under the `F-t` graph gives the impulse imparted to the body.

The magitude of total impulse of force on the body from
`t=4mu s` to `t=16mus=`area(`BCDFEB`)
`=`area of `BCFEB+`area `CDFC`
`=1/2(200+800)x2xx10^(-6)+1/2xx10xx800xx10^(-6)`
`=0.001+0.004=0.005Ns`