A stone of mass m tied to the end of a string, is whirled around in a horizontal circle. (Neglect the force due to gravity). The length of the string is reduced gradually keeping the angular momentum of the stone about the centre of the circle constant. Then, the tension in the string is given by `T = Ar^n` where A is a constant, r is the instantaneous radius of the circle and n=....

Explanation

To solve the problem, we need to analyze the motion of a stone tied to a string that is being whirled in a horizontal circle while keeping the angular momentum constant. Here’s a step-by-step solution:

### Step 1: Understand Angular Momentum
The angular momentum \( L \) of the stone is given by the formula:
\[ L = mvr \]
where \( m \) is the mass of the stone, \( v \) is the tangential velocity, and \( r \) is the radius of the circular path.
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