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When liquid medicine of density rho is t...

When liquid medicine of density `rho` is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop.
We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper.
If the radius of the opening of the dropper is r, the vertical force due to the surface tension on the drop of radius`R`(assuming `rlt ltR)` is

A

`2pirT`

B

`2piRT`

C

`2pir^(2)T//R`

D

`2piR^(2)T//r`

Text Solution

Verified by Experts

The correct Answer is:
C
Surface tension force `2pirT r/R=(2pir^(2)T)/R`
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When liquid medicine of density rho is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper. After the drop detaches, its surface energy is

When liquid medicine of density rho is to be put in the eye, it is done with the help of a dropper. As the bylb on the top of the dropper is pressed. A drop frons at the opening of the dropper. We wish to estimate the size of the drop. We first assume that the drop formed at the opening is spherical because that requires a minimum increase in its surface energy, To determine the size. We calculate the net vertical force due to the surface tension T when the radius of the drop is R. when this force become smaller than the weight of the drop the drop gets detached from the dropper. If r=5xx10^(-4)m,rho=10^(3) kg m^(-3), g=10ms^(-2), T=0.11Nm^(-1), The radius of the drop when it detaches from the dropper is approximately,

Knowledge Check

  • The pressure at depth h below the surface of a liquid of density rho open to the atmosphere is

    A
    greater than the atmospheric pressure by `rhogh`
    B
    less than the atmospheric pressure by `rhogh`
    C
    equal to the atmospheric pressure
    D
    increases exponentially with depth

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