Home
Class 11
PHYSICS
A small satellite revolves around a plan...

A small satellite revolves around a planet in an orbit just above planet's surface. Taking the mean density of the planet `8000 kg m^(-3)` and `G = 6.67 xx 10^(-11) N //kg^(-2)`, find the time period of the satellite.

Text Solution

AI Generated Solution

To find the time period of a small satellite revolving around a planet just above its surface, we can follow these steps: ### Step 1: Understand the formula for the time period of a satellite The time period \( T \) of a satellite in orbit can be expressed using the formula: \[ T = 2\pi \sqrt{\frac{r^3}{GM}} \] where: ...
Promotional Banner

Topper's Solved these Questions

  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Subjective|15 Videos
  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Single Correct|122 Videos
  • GRAVITATION

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 6.3|16 Videos
  • FLUID MECHANICS

    CENGAGE PHYSICS ENGLISH|Exercise INTEGER_TYPE|1 Videos
  • KINEMATICS-1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|9 Videos

Similar Questions

Explore conceptually related problems

A small satellite revolves round a planet in an orbit just above planet's surface. Taking the mean density of planet as rho , calculate the time period of the satellite.

A satellite revolve round a planet in an orbit just above the surface of a planet. Taking G = 6.67 xx 10^(-11) Nm^(2) kg^(2) and mean density of the planet 5.51 xx 10^(3) kg//m^(3) find the period of the planet.

The radius of the earth is 6.37 xx 10^(6) m and its mean density is 5.5 xx 10^(3) "kg m"^(-3) and G = 6.67 xx 10^(-11) "N-m"^(2) kg^(-2) Find the gravitational potential on the surface of the earth.

Two satellites A and B revolve around a plant in two coplanar circular orbits in the same sense with radii 10^(4) km and 2 xx 10^(4) km respectively. Time period of A is 28 hours. What is time period of another satellite?

Time period of a satellite in a circular obbit around a planet is independent of

The orbital speed of a satellite revolving around a planet in a circular orbit is v_(0) . If its speed is increased by 10 % ,then

The distance of the two planets from the Sun are 10^(13)m and 10^(12) m , respectively. Find the ratio of time periods of the two planets.

A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25xx10^(6)m above the surface of earth. If earth's radius is 6.38xx10^(6)m and g=9.8ms^(-2) , then the orbital speed of the satellite is

An artificial satellite is revolving in a circular orbit at a height of 1200 km above the surface of the earth. If the radius of the earth is 6400 km, mass is 6 xx 10^(24) kg find the orbital velocity (G = 6.67 xx 10^(-11)Nm^(2)//kg^(2))

Suppose there is an artificial satellite revolving round the planet mars at a height of 125 km. What is the orbital velocity of the artificial satellite. Radius of Mars is 3.375 xx 10^(6) m and the mass of the Mars is 6.420 xx 10^(23) kg .