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Measuring g
The figure shows a method for measuring the acceleration due to gravity. The ball is projected upward by a "gun". The ball passes electronic "gates" 1 and 2 as it rises and again as it falls. Each gate is connected to a separate timer. The first passage of the ball through each gate starts the corresponding timer, and the second passage through the same gate stops the timer. and the second passage through the same gate stops the timer. The time intervals `Deltat_1 and Deltat_2` are thus measured. The vertical distance between the two gates is d. If d = 5m, `Deltat_1 = 3s, Deltat_2 = 2s`, find the measured value of acceleration due to gravity `(in ms^(-2))`.
.

A

`8ms^(-2)`

B

`4ms^(-2)`

C

`2ms^(-2)`

D

`1ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(v_(1))/a=(/_\t_(1))/2=1.5`
`(v_(2))/a=(/_\t_(2))/2=1`
`d=(v_(1)^(2)-v_(2)^(2))/(2a)impliesa=8m//s^(2)`
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Figure shows a method for measuring the acceleration due to gravity. The ball is projected upward by a gun. The ball pases the electronic gates 1 and 2 as it rises and again as it falls. Each gate is connected to a separate timer. The first passage of the ball through each gate stars the corresponding timer, and the second passage through the same gate stops the timer. the time intervals /_\t_(1) and /_\t_(2) are thus measured. The vertical distance between the two gates is d . If d=5m, /_\t_(1)=3s, /_\t_(2)=2s , then find the measured value of acceleration due to gravity (in m//s^(2) )

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