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Two particles move on a circular path (o...

Two particles move on a circular path (one just inside and the other just outside) with the angular velocities `omega` and `5omega` starting from the same point. Then

A

the cross each other at regular intervals of time `2pi//4omega` when their angular velocities are oppositely directed

B

they cross each other at point on the path subtending an angle of `60^@` at the centre if their angular velocities are oppositely directed

C

the cross at intervals of time `pi//3omega` if their angular velocities are oppositely directed

D

they cross each other at points on the path subtendingf `90^` at the centre if their angular velocities are in the same sence

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To solve the problem, we need to analyze the motion of two particles moving on a circular path with different angular velocities. Let's break down the solution step by step. ### Step 1: Define the Problem We have two particles moving on a circular path: - Particle A moves with angular velocity \( \omega \). - Particle B moves with angular velocity \( 5\omega \). They start from the same point on the circle. ### Step 2: Determine the Time of Intersection Since they are moving in opposite directions, we can set up the equations for their angular positions at time \( t \): - For Particle A: \( \theta_A = \omega t \) - For Particle B: \( \theta_B = 2\pi - 5\omega t \) ### Step 3: Set Up the Equation for Intersection The particles will cross each other when their angular positions are equal: \[ \omega t = 2\pi - 5\omega t \] Rearranging gives: \[ \omega t + 5\omega t = 2\pi \] \[ 6\omega t = 2\pi \] \[ t = \frac{2\pi}{6\omega} = \frac{\pi}{3\omega} \] ### Step 4: Calculate the Angle Subtended Now, we can find the angle \( \theta \) subtended at the center by Particle A when they meet: \[ \theta = \omega t = \omega \left(\frac{\pi}{3\omega}\right) = \frac{\pi}{3} \] This means \( \theta = 60^\circ \). ### Step 5: Analyze the Options Now we can analyze the options given in the problem: 1. They cross each other at regular intervals of time \( \frac{2\pi}{4\omega} \) - **Not Correct**. 2. They cross each other at points on the path subtending an angle \( \theta = 60^\circ \) - **Correct**. 3. They cross at intervals of time \( \frac{\pi}{3\omega} \) - **Correct**. 4. They cross each other at points on the path subtending an angle \( 90^\circ \) when moving in the same sense - **Correct**. ### Conclusion The correct options are B, C, and D.

To solve the problem, we need to analyze the motion of two particles moving on a circular path with different angular velocities. Let's break down the solution step by step. ### Step 1: Define the Problem We have two particles moving on a circular path: - Particle A moves with angular velocity \( \omega \). - Particle B moves with angular velocity \( 5\omega \). They start from the same point on the circle. ...
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