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A single wire ACB passes through a smoot...

A single wire `ACB` passes through a smooth ring at `C` when revolves at a constant speed in the horizontal circle of radius `r=6.4m` as shown in the figure. Find the speed (in `m//s)` of revolution of the ring.

Text Solution

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The correct Answer is:
8
Tension in both parts of the string will be the same
`Tcos30^@+Tcos60^@=mg`…………i
`Tcos30^@+Tcos60^@=mv^2//r`…………ii
From eqn i and ii `v=sqrt(gr)=sqrt(10xx6.4)=8m//s`
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