Home
Class 11
PHYSICS
Two wheels, each marked with a dot on it...

Two wheels, each marked with a dot on its rim, are mounted side by side. Initially the dots are alinged and wheels are at rest. One of the wheels is given a constant angular acceleration of `(pi//2) rad//sec^(2)` and the other wheel is given a constant angular acceleration `(pi//4)rad//sec^(2)`. Both acceleration are in the same direction. Find the time (in s) after which the two dots will becomes alingned again for the first time.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of when the two dots on the wheels will align again, we can follow these steps: ### Step 1: Understand the problem We have two wheels with different angular accelerations. We need to find the time at which the dots on their rims will align again after being initially aligned. ### Step 2: Define the angular displacements Let: - \( \alpha_1 = \frac{\pi}{2} \, \text{rad/s}^2 \) (angular acceleration of the first wheel) - \( \alpha_2 = \frac{\pi}{4} \, \text{rad/s}^2 \) (angular acceleration of the second wheel) The angular displacement \( \theta \) for each wheel can be calculated using the formula: \[ \theta = \frac{1}{2} \alpha t^2 \] ### Step 3: Write the equations for angular displacements For the first wheel: \[ \theta_1 = \frac{1}{2} \alpha_1 t^2 = \frac{1}{2} \cdot \frac{\pi}{2} \cdot t^2 = \frac{\pi}{4} t^2 \] For the second wheel: \[ \theta_2 = \frac{1}{2} \alpha_2 t^2 = \frac{1}{2} \cdot \frac{\pi}{4} \cdot t^2 = \frac{\pi}{8} t^2 \] ### Step 4: Set the condition for alignment The two dots will align again when the angular displacements are equal to an integer multiple of \( 2\pi \): \[ \theta_1 = 2\pi n_1 \quad \text{and} \quad \theta_2 = 2\pi n_2 \] where \( n_1 \) and \( n_2 \) are integers representing the number of complete rotations. ### Step 5: Relate the two equations From the equations for \( \theta_1 \) and \( \theta_2 \): \[ \frac{\pi}{4} t^2 = 2\pi n_1 \quad \text{(1)} \] \[ \frac{\pi}{8} t^2 = 2\pi n_2 \quad \text{(2)} \] ### Step 6: Simplify the equations From equation (1): \[ t^2 = 8 n_1 \] From equation (2): \[ t^2 = 16 n_2 \] ### Step 7: Set the equations equal to each other Since both expressions equal \( t^2 \): \[ 8 n_1 = 16 n_2 \] This simplifies to: \[ \frac{n_1}{n_2} = \frac{16}{8} = 2 \] Thus, we can set \( n_1 = 2 \) and \( n_2 = 1 \). ### Step 8: Substitute back to find \( t \) Substituting \( n_1 = 2 \) into the equation for \( t^2 \): \[ t^2 = 8 \cdot 2 = 16 \] Thus, \[ t = \sqrt{16} = 4 \, \text{s} \] ### Final Answer The time after which the two dots will become aligned again for the first time is **4 seconds**. ---

To solve the problem of when the two dots on the wheels will align again, we can follow these steps: ### Step 1: Understand the problem We have two wheels with different angular accelerations. We need to find the time at which the dots on their rims will align again after being initially aligned. ### Step 2: Define the angular displacements Let: - \( \alpha_1 = \frac{\pi}{2} \, \text{rad/s}^2 \) (angular acceleration of the first wheel) ...
Promotional Banner

Topper's Solved these Questions

  • MISCELLANEOUS VOLUME 2

    CENGAGE PHYSICS ENGLISH|Exercise LC_TYPE|34 Videos
  • MISCELLANEOUS KINEMATICS

    CENGAGE PHYSICS ENGLISH|Exercise Interger type|3 Videos
  • NEWTON'S LAWS OF MOTION 1

    CENGAGE PHYSICS ENGLISH|Exercise Integer|5 Videos

Similar Questions

Explore conceptually related problems

A wheel rotates with a constant angular velocity of 300 rpm. The angle through which the wheel rotates in 1 s is.

A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/ sec^(2) ?

A particle is moving with a constant angular acceleration of 4rad//s^(2) in a circular path. At time t=0 , particle was at rest. Find the time at which the magnitudes of centripetal acceleration and tangential acceleration are equal.

Find the total acceleration of a particle, moving in a circular track of radius 2 m, with constant angular acceleration of 1 rad//sec^(2) at time t = 2 seconds from the center

A wheel starts rotating with an-angular velocity of 2 rad/s. If it rotates with a constant angular acceleration 4 "rad/s"^2 what angle does the wheel rotate through in 2.0 s ? What is the angular speed, after 2.0 s.

A wheel rotates with a constant acceleration of 2.0(rad)/s^2 . If the wheel starts from rest, how many revolutions will it make in the first 10 seconds?

Starting from rest a wheel rotates with uniform angular acceleration 2pirads^(-2) . After 4s, if the angular acceleration ceases to act, its angular displacement in the next 4s is

A torque of 2 newton-m produces an angular acceleration of 2 rad//sec^(2) a body. If its radius of gyration is 2m, its mass will be:

Compute the torque acting on a wheel of moment of inertia 10kgm^(2) , moving with angular acceleration 5 rad s^(-2) .

Compute the torque acting on a wheel of moment of inertia 10kgm^(2) , moving with angular acceleration 5 rad s^(-2) .