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We have three identical metallic spheres...

We have three identical metallic spheres `A,B, and C`. `A` is given a charge `Q, and B and C` are uncharged. The following processes of touching of two spheres are carried out in succession. Each process is carried out with sufficient time. ltbgt i. A and B
ii. B and C
iii. C and A
iv. A and B
v. B and C
The final charges on the spheres are.

A

`(11 Q)/(32), (5 Q)/(16),(11 Q)/(32)`

B

`(11Q)/(32),(11 Q)/(32), (5 Q)/(16)`

C

`(8 Q)/(8),(5Q)/(16),(5 Q)/(16)`

D

`(5 Q)/(16), (11 Q)/(32),(11 Q)/(32)`

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To solve the problem step by step, we will analyze the charge distribution on the spheres after each touching process. ### Step 1: Initial Charges - Sphere A has a charge \( Q \). - Sphere B and Sphere C are uncharged, so they have charges of \( 0 \). ### Step 2: Touching A and B When spheres A and B are touched, the total charge is distributed equally between them since they are identical spheres. - Initial charge on A = \( Q \) - Initial charge on B = \( 0 \) - Total charge = \( Q + 0 = Q \) - After touching, the charge on each sphere: \[ Q_{A} = Q_{B} = \frac{Q}{2} \] - Final charges: - Sphere A: \( \frac{Q}{2} \) - Sphere B: \( \frac{Q}{2} \) - Sphere C: \( 0 \) ### Step 3: Touching B and C Now we touch spheres B and C. - Initial charge on B = \( \frac{Q}{2} \) - Initial charge on C = \( 0 \) - Total charge = \( \frac{Q}{2} + 0 = \frac{Q}{2} \) - After touching, the charge on each sphere: \[ Q_{B} = Q_{C} = \frac{\frac{Q}{2}}{2} = \frac{Q}{4} \] - Final charges: - Sphere A: \( \frac{Q}{2} \) - Sphere B: \( \frac{Q}{4} \) - Sphere C: \( \frac{Q}{4} \) ### Step 4: Touching C and A Next, we touch spheres C and A. - Initial charge on C = \( \frac{Q}{4} \) - Initial charge on A = \( \frac{Q}{2} \) - Total charge = \( \frac{Q}{4} + \frac{Q}{2} = \frac{Q}{4} + \frac{2Q}{4} = \frac{3Q}{4} \) - After touching, the charge on each sphere: \[ Q_{C} = Q_{A} = \frac{\frac{3Q}{4}}{2} = \frac{3Q}{8} \] - Final charges: - Sphere A: \( \frac{3Q}{8} \) - Sphere B: \( \frac{Q}{4} \) - Sphere C: \( \frac{3Q}{8} \) ### Step 5: Touching A and B Again Now we touch spheres A and B again. - Initial charge on A = \( \frac{3Q}{8} \) - Initial charge on B = \( \frac{Q}{4} \) - Total charge = \( \frac{3Q}{8} + \frac{Q}{4} = \frac{3Q}{8} + \frac{2Q}{8} = \frac{5Q}{8} \) - After touching, the charge on each sphere: \[ Q_{A} = Q_{B} = \frac{\frac{5Q}{8}}{2} = \frac{5Q}{16} \] - Final charges: - Sphere A: \( \frac{5Q}{16} \) - Sphere B: \( \frac{5Q}{16} \) - Sphere C: \( \frac{3Q}{8} \) ### Step 6: Touching B and C Again Finally, we touch spheres B and C. - Initial charge on B = \( \frac{5Q}{16} \) - Initial charge on C = \( \frac{3Q}{8} \) - Total charge = \( \frac{5Q}{16} + \frac{3Q}{8} = \frac{5Q}{16} + \frac{6Q}{16} = \frac{11Q}{16} \) - After touching, the charge on each sphere: \[ Q_{B} = Q_{C} = \frac{\frac{11Q}{16}}{2} = \frac{11Q}{32} \] - Final charges: - Sphere A: \( \frac{5Q}{16} \) - Sphere B: \( \frac{11Q}{32} \) - Sphere C: \( \frac{11Q}{32} \) ### Final Result - Final charges on the spheres are: - Sphere A: \( \frac{5Q}{16} \) - Sphere B: \( \frac{11Q}{32} \) - Sphere C: \( \frac{11Q}{32} \)

To solve the problem step by step, we will analyze the charge distribution on the spheres after each touching process. ### Step 1: Initial Charges - Sphere A has a charge \( Q \). - Sphere B and Sphere C are uncharged, so they have charges of \( 0 \). ### Step 2: Touching A and B When spheres A and B are touched, the total charge is distributed equally between them since they are identical spheres. ...
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