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In the circuit shown in figure C = 6 muF...

In the circuit shown in figure `C = 6 muF`. The charge stored in the capacitor of capacity C is

A

zero

B

`90 muC`

C

`40 muC`

D

`60 muC`

Text Solution

Verified by Experts

The correct Answer is:
C
`0-Q/C+10-Q/(2C)=0`
`Q=(20C)/3=(20xx6)/3=40 muC`.
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