For the system shown in capacitance is `C` The left plate is given a charge `Q_(1)` and the is closed.
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Find the amount of charge that will flow through the battery before the steady state is achieved.

Options

A. `CV`
B. `CV-Q_(1)`
C. `CV+Q_(1)/2`
D. `CV-Q_(1)/2`

Answer

D

Explanation

`Q=CV`
Charge flow is `Deltaq=(Q+Q_(1)/2)-Q_(1)`
`Q-Q_(1)/2=CV-Q_(1)/2`
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and charge on the inner surface of the left plate is `Q=CV`.