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For the system shown in capacitance is ...

For the system shown in capacitance is `C` The left plate is given a charge `Q_(1)` and the switch is closed.
.
Find the charge appearing on the inner face of the left plate.

A

`CV-Q_(1)/2`

B

`CV+Q_(1)`

C

`CV+Q_(1)/2`

D

`CV`

Text Solution

Verified by Experts

The correct Answer is:
D
`Q=CV`
Charge flow is `Deltaq=(Q+Q_(1)/2)-Q_(1)`
`Q-Q_(1)/2=CV-Q_(1)/2`
.
and charge on the inner surface of the left plate is `Q=CV`.
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