A wire of mass m length I, density d, and area of cross section A is stretched in such a way that is length increases by 10% of its original value, Expresss the changed resistance in percentage.

Explanation

To solve the problem step by step, we will follow the reasoning laid out in the video transcript.

### Step 1: Identify the original length and the change in length
The original length of the wire is denoted as \( L \). The wire is stretched such that its length increases by 10% of its original length. Therefore, the new length \( L' \) after stretching can be calculated as:

\[ L' = L + 0.1L = 1.1L \]
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