An uncharged capacitor is connected to a 15 V battery through a resistance of `10Omega.` It is found that in a time of `2mus,` potential difference across the capacitor becomes 5V. Find the capacitance of the Capacitor. Take ln(1.5) = 0.4.

Explanation

To find the capacitance of the capacitor in the given circuit, we can follow these steps:

### Step 1: Understand the Circuit
We have a capacitor connected to a 15 V battery through a 10 Ω resistor. The capacitor is initially uncharged.

### Step 2: Use the Charging Formula
The charge \( Q \) on a capacitor at any time \( t \) while charging is given by:
\[
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