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find the potential difference between th point A and B and between the point B and C of figure in steady state.

Text Solution

Verified by Experts

Applying Kirchhoff's law in loop AQBRC, we get
`-(q)/(6) - (q)/(2) +100 = 0 or q= 150muC`

Therefore, the potential difference between AB is 150//6
=25 V and potential differecne between BC is 100 -25 =75V.
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