A capacitor of capacitance `10muF` is connected to a resistance `2Omega` and a battery of emf 5V of negligible interanl resistance. After `20mus` of comleting the circuit find.
a. power delivered by the battery
b. power dissipated as heat
c. rate of energy stored in the capacitor

Explanation

To solve the problem step by step, we will calculate the power delivered by the battery, the power dissipated as heat in the resistor, and the rate of energy stored in the capacitor.

### Given:
- Capacitance, \( C = 10 \, \mu F = 10 \times 10^{-6} F \)
- Resistance, \( R = 2 \, \Omega \)
- EMF of the battery, \( V_0 = 5 \, V \)
- Time after completing the circuit, \( t = 20 \, \mu s = 20 \times 10^{-6} s \)

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