A dynamo develops `0.5 A` at `6 V`. Find the energy it generated in `1 s`.

Explanation

To find the energy generated by the dynamo in 1 second, we can follow these steps:

### Step 1: Understand the relationship between power and energy
Power (P) is defined as the rate at which energy is generated or consumed. The formula for power is given by:
\[ P = \frac{E}{t} \]
where \( E \) is the energy in joules, and \( t \) is the time in seconds.

### Step 2: Use the formula for power in electrical circuits
In an electrical circuit, the power can also be calculated using the formula:
\[ P = V \times I \]
where \( V \) is the voltage in volts, and \( I \) is the current in amperes.

### Step 3: Substitute the given values
From the problem, we know:
- Current \( I = 0.5 \, \text{A} \)
- Voltage \( V = 6 \, \text{V} \)

Now, substituting these values into the power formula:
\[ P = 6 \, \text{V} \times 0.5 \, \text{A} \]
\[ P = 3 \, \text{W} \]

### Step 4: Calculate the energy generated in 1 second
Since we are asked for the energy generated in 1 second, we can use the power calculated:
\[ E = P \times t \]
Here, \( t = 1 \, \text{s} \):
\[ E = 3 \, \text{W} \times 1 \, \text{s} \]
\[ E = 3 \, \text{J} \]

### Final Answer
The energy generated by the dynamo in 1 second is **3 joules**.

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