The galvanometer shown in the figure has resistance `10Omega.` It is shunted by a series combination of a resistance `S = 1Omega` and an ideal cell of emf 2 V. A current 2 A passes as shown.

Options

A. The reading of the galvanometer is 1A.
B. The reading of the galvanometer is zero.
C. The potential difference across the resistance S is 1.5 V.
D. The potential difference across the resistance S is 2 V.

Answer

A, B, D

Explanation

a.,b.,d.
Let the currents be as shown in
the figure.
Applying KVL along ABCDA,
we get
`-10i-2 + (2-i) 1 = 0`
`:. i = 0 `
Potential difference across = `(2-i)1 = 2xx1 = 2V` .