Current through the battery in the circuit shown in the figure

Options

A. immediately after the switch S is closed is `epsilon//R`
B. immediately after the switch S is closed is `epsilon //2R`.
C. after long time is `epsilon//2R`.
D. after long time is `3epsilon//4R`

Answer

A, C

Explanation

a., c.
Immediately after closing the switch, the capacitor will behave
like conducting wires, so all the resistances between B and G
will be short-circuited and current will flow through ABFEG.
Hence current `= epsilon//R`. After long time when the capacitors are
fully charged, current will go through ABDG. Hence current =
`epsilon//2R` .