In the circuit, various resistance and five batteries are connected as shown in the figure. If point O is earthed,

Answer

A, C, D

Explanation

a.,c.,d.

From circuit diagram it is clear
`I_1 = (15-5)/6 = 2A, I_2 = (15-10)/2 = 2.5A`
Taking branch xM
`15 + 2I_3 - 15 = 10 or I_3 = 5A`
Taking branch N O
`5+5-5I_4 = 0 or I_4 = 2A`
In junction `x: I_3 = I_1 + I_2 + I_A`
`5 = 2+ 2.5 = I_A or I_A = 1/2 A`
In junction B: ` I_1 + I_A = I_4 + I_B`
or `2.0 + 0.5 = 2 + I_(B) or I_(B) = 1/2 A`.