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An electric bulb rated for 500 W at 100 ...

An electric bulb rated for `500 W` at `100 V` is used in a circuit having a `200 V` supply. The reistance `R` that must be put in series with bulb, so that the bulb delivers `500 `W is ……….`Omega`.

Text Solution

Verified by Experts

We know that `P = V^2/R`
`:. R = V^2/P = (100 xx 100)/500 = 20 Omega`
For the bulb to deliver 500 W, it should have a potential difference of 100 V across it. This would be possible only when `R = 20 Omega`. Because in that case, both resistances will share equal potential difference and the potential difference across the bulb will be 200 V. Hence, the answer is `20Omega.`
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