For the circuit shown in figure

Options

A. the current I through the battery is 7.5 mA
B. the potential difference across `R_L` is 18 V
C. ratio of powers dissipated in `R_1` to that in `R_2` is 3
D. if `R_1 and R_2` are interchanged, the magnitude of the power dissipated in `R_L` c

Answer

A, D

Explanation

a., d.
`24 - 2 xx 10^3I - 6 xx 10^3 (I-i) = 0`
`24 - 2 xx 10^3 I - 1.5 xx 10^3i = 0`
Hence, `I = 7.5 mA`
`I = 6mA`
`24 - 6 xx 10^3 I - 2 xx 10^3 (I-i) = 0`
`24 - 6 xx 10^3I - 1.5 xx 10^3 i = 0`
I = 3.5 mA`
`i = 2mA`
`P_1/P_2 = 6^2/2^2 = 9`
, .