A beam of light propagates through a medium 1 and falls onto another medium 2, at an angle `alpha_(1)` as shown in figure. After that, it propagates in medium 2 at an angle `alpha_(2)` as shown. The light's wavelength in medium 1 is `lambda_(1)`. What is the wavelength of light in medium

Options

A. `(sinalpha_(1))/(sinalpha_(2))lambda_(1)`
B. `(sinalpha_(2))/(sinalpha_(1))lambda_(1)`
C. `(cosalpha_(1))/(cosalpha_(2))lambda_(1)`
D. `(cosalpha_(2))/(cosalpha_(1))lambda_(1)`

Answer

b.

Explanation

`mu_(1)sinalpha=mu_(2)sinalpha_(2)`
`(c)/(v_(1))sinalpha_(1)=(c)/(v_(2))sinalpha_(2)`
`(sinalpha_(1))/(flamda_(1))=(sinalpha_(2))/(flambda_(2))`