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Two thin lenses are placed 5cm apart alo...

Two thin lenses are placed 5cm apart along the same axis and illuminted with a beam of light parallel to that axis. The first lens in the path of the beam is a converging lens of focal length 10cm whereas the second is a diverging lens of focal length 5cm. If the second lens if now moved toward the first, the emergent light

A

remains parallel

B

remains convergent

C

remains divergent

D

changes form parallel to divergent

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To solve the problem step by step, we will analyze the situation involving two lenses: a converging lens and a diverging lens, and how the emergent light changes when the diverging lens is moved closer to the converging lens. ### Step 1: Understand the Lens System We have two lenses: - **Lens 1**: Converging lens with a focal length (f1) of 10 cm. - **Lens 2**: Diverging lens with a focal length (f2) of -5 cm (negative because it is a diverging lens). The distance between the two lenses is given as 5 cm. ### Step 2: Analyze the Initial Condition When parallel rays of light (from a distant source) strike the converging lens (Lens 1), they converge to a point at its focal length, which is 10 cm from Lens 1. **Position of the Image Formed by Lens 1**: - The rays converge at a point 10 cm from Lens 1, which is 5 cm away from Lens 2 (since the distance between the lenses is 5 cm). - Therefore, the image formed by Lens 1 acts as an object for Lens 2 and is located at a distance of 5 cm from Lens 2. ### Step 3: Determine the Nature of the Rays After Lens 1 Since the image formed by Lens 1 is at the focal point of Lens 2 (which is 5 cm), the rays emerging from Lens 2 will be parallel to each other. This is because when the object is at the focal point of a diverging lens, the emergent rays are parallel. ### Step 4: Moving the Diverging Lens Now, if we move Lens 2 (the diverging lens) closer to Lens 1, the distance between the two lenses becomes less than 5 cm. ### Step 5: Analyze the New Condition As Lens 2 moves closer to Lens 1, the image formed by Lens 1 will still be the same, but now the object distance for Lens 2 becomes less than its focal length. **New Object Distance for Lens 2**: - The object distance for Lens 2 is now less than 5 cm (the distance between the lenses is reduced). ### Step 6: Determine the Nature of the Rays After Lens 2 When the object distance for Lens 2 is less than its focal length (5 cm), the rays that enter Lens 2 will diverge after passing through it. Thus, the emergent rays from Lens 2 will be divergent. ### Conclusion Initially, the emergent rays from the system were parallel. After moving the diverging lens closer to the converging lens, the emergent rays become divergent. ### Final Answer The emergent light changes from parallel to divergent. ---

To solve the problem step by step, we will analyze the situation involving two lenses: a converging lens and a diverging lens, and how the emergent light changes when the diverging lens is moved closer to the converging lens. ### Step 1: Understand the Lens System We have two lenses: - **Lens 1**: Converging lens with a focal length (f1) of 10 cm. - **Lens 2**: Diverging lens with a focal length (f2) of -5 cm (negative because it is a diverging lens). The distance between the two lenses is given as 5 cm. ...
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