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The lateral magnification of the lens wi...

The lateral magnification of the lens with an object located at two different position `u_(1)` and `u_(2)` are `m_(1)` and `m_(2)` , respectively. Then the focal length of the lens is

A

`f=sqrt(m_(1)m_(2))(mu_(2)-mu_(1))`

B

`f=sqrt(m_(1)m_(2))(u_(2)-u_(1))`

C

`((u_(2)-u_(1)))/(sqrt(m_(1)m_(2)))`

D

`((u_(2)-u_(1)))/((m_(2))^(-1)-(m_(1))^(-1))`

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The correct Answer is:
To find the focal length of the lens given the lateral magnifications \( m_1 \) and \( m_2 \) for object positions \( u_1 \) and \( u_2 \), we can follow these steps: ### Step 1: Understand the relationship between magnification and focal length The lateral magnification \( m \) of a lens is given by the formula: \[ m = \frac{v}{u} \] where \( v \) is the image distance and \( u \) is the object distance. Additionally, for a thin lens, we have the lens formula: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] ### Step 2: Write the magnification equations for both positions For the first object position \( u_1 \): \[ m_1 = \frac{v_1}{u_1} \implies v_1 = m_1 u_1 \] Substituting \( v_1 \) in the lens formula gives: \[ \frac{1}{f} = \frac{1}{m_1 u_1} + \frac{1}{u_1} \] This simplifies to: \[ \frac{1}{f} = \frac{1 + m_1}{m_1 u_1} \] For the second object position \( u_2 \): \[ m_2 = \frac{v_2}{u_2} \implies v_2 = m_2 u_2 \] Substituting \( v_2 \) in the lens formula gives: \[ \frac{1}{f} = \frac{1}{m_2 u_2} + \frac{1}{u_2} \] This simplifies to: \[ \frac{1}{f} = \frac{1 + m_2}{m_2 u_2} \] ### Step 3: Set the two expressions for \( \frac{1}{f} \) equal to each other From the two equations derived, we have: \[ \frac{1 + m_1}{m_1 u_1} = \frac{1 + m_2}{m_2 u_2} \] ### Step 4: Cross-multiply and rearrange Cross-multiplying gives: \[ (1 + m_1) m_2 u_2 = (1 + m_2) m_1 u_1 \] Rearranging this equation will help in isolating \( f \). ### Step 5: Solve for \( f \) After rearranging, we can express \( f \) in terms of \( m_1, m_2, u_1, \) and \( u_2 \). The final expression for the focal length \( f \) can be derived from the differences in magnifications and object distances: \[ f = \frac{(u_2 - u_1)(m_2 - m_1)}{m_1 m_2} \] ### Final Expression Thus, the focal length \( f \) can be expressed as: \[ f = \frac{(u_2 - u_1)(m_2 - m_1)}{m_1 m_2} \]

To find the focal length of the lens given the lateral magnifications \( m_1 \) and \( m_2 \) for object positions \( u_1 \) and \( u_2 \), we can follow these steps: ### Step 1: Understand the relationship between magnification and focal length The lateral magnification \( m \) of a lens is given by the formula: \[ m = \frac{v}{u} \] where \( v \) is the image distance and \( u \) is the object distance. Additionally, for a thin lens, we have the lens formula: ...
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CENGAGE PHYSICS ENGLISH-GEOMETRICAL OPTICS-Single Correct
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