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Find the net deviation produced in the i...

Find the net deviation produced in the incident ray for the optical instrument shown in figure. (Take refractive index of the prism material as 2.)

A

`66^(@)CW`

B

`66^(@)ACW`

C

`54^(@)ACW`

D

`54^(@)CW`

Text Solution

Verified by Experts

The correct Answer is:
D
Deviation produced by the mirror is
`delta_(1)=pi-2xx60=60^(@)CW`
Deviation produced by the prism is
`delta_(2)=(1-2)xx6=6^(@)ACW`
So, net deviation, `delta=delta+delta_(2)=(60^(@)-6^(@))CW=54^(@)CW`
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