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For a prism its refractive index is cot ...

For a prism its refractive index is cot A/2 then minimum angle of deviation is :

A

`180^(@)-3A`

B

`180^(@)+3A`

C

`90^(@)-3A`

D

`180^(@)-2A`

Text Solution

Verified by Experts

The correct Answer is:
d.
From `sin((A+delta_(m))/(2))=mu "sin"(A)/(2)`
`sin((A+delta_(m))/(2))=("cos"(A)/(2))/("sin"(A)/(2))xx"sin"(A)/(2)`
`(A+delta_(m))/(2)=(pi)/(2)-(A)/(2)`
`delta_(m)=pi-2A=180^(@)-2A`
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