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A converging lens of focal length f(1) i...

A converging lens of focal length `f_(1)` is placed in front of and coaxially with a convex mirror of focal length `f_(2)`. Their separation is d. A parallel beam of light incident on the lens returns as a parallel beam from the arrangement, Then,

A

the beam diameters of the incident and reflected beams must be the same

B

`d=f_(1)-2|f_(2)|`

C

`d=f_(1)-|f_(2)|`

D

if the entire arrangement is immersed in water, the conditions will remain unaltered

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The correct Answer is:
To solve the problem, we need to analyze the arrangement of the converging lens and the convex mirror, and understand the conditions under which a parallel beam of light incident on the lens returns as a parallel beam after reflection from the mirror. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a converging lens with focal length \( f_1 \). - A convex mirror with focal length \( f_2 \) is placed coaxially behind the lens. - The distance between the lens and the mirror is \( d \). 2. **Condition for Parallel Beams**: - A parallel beam of light incident on the lens will converge to its focal point \( f_1 \). - After passing through the lens, the rays will converge at a point located at a distance \( f_1 \) from the lens. 3. **Reflection from the Convex Mirror**: - The rays that converge at the focal point \( f_1 \) will then strike the convex mirror. - For the rays to return as a parallel beam after reflection from the convex mirror, they must behave as if they are coming from the focal point of the mirror. 4. **Using the Focal Length of the Mirror**: - The focal length \( f_2 \) of the convex mirror is defined as the distance from the mirror to the point where parallel rays converge after reflection. - The distance from the lens to the mirror is \( d \), so the effective distance from the focal point of the lens to the mirror is \( d - f_1 \). 5. **Setting Up the Equation**: - For the rays to retrace their path and return as parallel, the distance \( d - f_1 \) must equal \( f_2 \) (the focal length of the mirror). - Therefore, we can write the equation: \[ d - f_1 = f_2 \] - Rearranging gives: \[ d = f_1 + f_2 \] 6. **Considering the Object Distance for the Mirror**: - The object distance for the mirror when the rays converge at the focal point is \( 2f_2 \) (since the object must be at twice the focal length for the rays to return parallel). - Thus, we have another relationship: \[ d = 2f_2 \] 7. **Equating the Two Expressions for \( d \)**: - From the two equations we derived: \[ f_1 + f_2 = 2f_2 \] - Simplifying gives: \[ f_1 = f_2 \] 8. **Conclusion**: - The conditions for the parallel beam to return parallel after reflection are satisfied when \( d = f_1 + f_2 \) and \( f_1 = f_2 \). ### Final Answer: The relationship between the focal lengths and the separation distance is: \[ d = f_1 + f_2 \]

To solve the problem, we need to analyze the arrangement of the converging lens and the convex mirror, and understand the conditions under which a parallel beam of light incident on the lens returns as a parallel beam after reflection from the mirror. ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have a converging lens with focal length \( f_1 \). - A convex mirror with focal length \( f_2 \) is placed coaxially behind the lens. - The distance between the lens and the mirror is \( d \). ...
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CENGAGE PHYSICS ENGLISH-GEOMETRICAL OPTICS-Single Correct
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