Home
Class 12
PHYSICS
A beam of light converges towards a poin...

A beam of light converges towards a point O, behind a convex mirror of focal length 20cm.
Q. Similarly, as in above question when point O is 30cm behind the mirror.

A

`2`(virtual, inverted)

B

`3`(real, inverted)

C

`3`(virtual, enlarged)

D

`1(`real, enlarged)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the concepts of geometrical optics, specifically focusing on the convex mirror and its properties. ### Step 1: Identify the Given Values - Focal length of the convex mirror (f) = +20 cm (positive because it is a convex mirror) - Distance of the object (u) = -30 cm (negative because the object is behind the mirror) ### Step 2: Use the Mirror Formula The mirror formula is given by: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] Where: - \( f \) = focal length - \( v \) = image distance - \( u \) = object distance ### Step 3: Substitute the Values into the Mirror Formula Substituting the values of \( f \) and \( u \) into the mirror formula: \[ \frac{1}{20} = \frac{1}{v} + \frac{1}{-30} \] ### Step 4: Rearrange the Equation Rearranging the equation gives: \[ \frac{1}{v} = \frac{1}{20} + \frac{1}{30} \] ### Step 5: Find a Common Denominator The common denominator for 20 and 30 is 60. Thus, we can rewrite the fractions: \[ \frac{1}{20} = \frac{3}{60}, \quad \frac{1}{30} = \frac{2}{60} \] So, \[ \frac{1}{v} = \frac{3}{60} + \frac{2}{60} = \frac{5}{60} \] ### Step 6: Calculate the Image Distance (v) Now, taking the reciprocal to find \( v \): \[ v = \frac{60}{5} = 12 \text{ cm} \] (Note: The positive sign indicates that the image is virtual and located behind the mirror.) ### Step 7: Calculate the Magnification (M) The magnification (M) is given by the formula: \[ M = -\frac{v}{u} \] Substituting the values of \( v \) and \( u \): \[ M = -\frac{12}{-30} = \frac{12}{30} = \frac{2}{5} \] ### Step 8: Interpret the Results The magnification of \( \frac{2}{5} \) means that the image is virtual, upright, and smaller than the object. ### Final Results - Image distance (v) = 12 cm (behind the mirror) - Magnification (M) = \( \frac{2}{5} \)

To solve the problem step by step, we will follow the concepts of geometrical optics, specifically focusing on the convex mirror and its properties. ### Step 1: Identify the Given Values - Focal length of the convex mirror (f) = +20 cm (positive because it is a convex mirror) - Distance of the object (u) = -30 cm (negative because the object is behind the mirror) ### Step 2: Use the Mirror Formula The mirror formula is given by: ...
Promotional Banner

Topper's Solved these Questions

  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Integer|15 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Archives|7 Videos
  • GEOMETRICAL OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Assertion-Reasoninig|2 Videos
  • ELECTRON,PHONTS,PHOTOELECTRIC EFFECT & X-RAYS

    CENGAGE PHYSICS ENGLISH|Exercise dpp 3.3|15 Videos
  • HEATING EFFECT OF CURRENT

    CENGAGE PHYSICS ENGLISH|Exercise Thermal Power in Resistance Connected in Circuit|27 Videos

Similar Questions

Explore conceptually related problems

A beam of light converges towards a point O, behind a convex mirror of focal length 20cm. Q. Find the magnification and nature of the image when point O is 10cm behind the mirror.

From a concave mirror of focal length 20 cm. match the following:

For a concave mirror of focal length 20 cm, match the following

An object is placed at 20 cm from a convex mirror of focal length 10 cm. The image formed by a mirror is

The image formed by a convex mirror of focal length 30 cm . is a quarter of the object. What is the distance of the object from the mirror ?

An object is placed at 20 cm from a convex mirror of focal length 20 cm. The distance of the image from the pole of the mirror is

A concave mirror of focal length 10cm and a convex mirror of focal length 15cm are placed facing each other 40cm apart. A point object is placed between the mirrors, on their common axis and 15cm from the concave mirror. Find the position and nature of the image produced by successive reflections, first at the concave mirror and then at the convex mirror.

Focal length of a convex mirror is 10 cm

An object is placed at a distance 20 cm from the pole of a convex mirror of focal length 20 cm. The image is produced at

Figure given below shows a beam of light converging at point P. When a concave lens of focal length 16cm is introduced in the path of the beam at a place O shown by dotted line such that OP becomes the axis of the lens, the beam converges at a distance x from the lens. The value x will be equal to

CENGAGE PHYSICS ENGLISH-GEOMETRICAL OPTICS-Linked Comprehension
  1. Two identical plano-convex lenses L(1)(mu(1)-1.4) and L(2)(mu(2)-1.5) ...

    Text Solution

    |

  2. A beam of light converges towards a point O, behind a convex mirror of...

    Text Solution

    |

  3. A beam of light converges towards a point O, behind a convex mirror of...

    Text Solution

    |

  4. A ray of light enters a spherical drop of water of refractive index mu...

    Text Solution

    |

  5. A ray of light enters a spherical drop of water of refractive index mu...

    Text Solution

    |

  6. A ray of light enters a spherical drop of water of refractive index mu...

    Text Solution

    |

  7. The ciliary muscles of eye control the curvature of the lens in the ey...

    Text Solution

    |

  8. The ciliary muscles of eye control the curvature of the lens in the ey...

    Text Solution

    |

  9. The ciliary muscles of eye control the curvature of the lens in the ey...

    Text Solution

    |

  10. The ciliary muscles of eye control the curvature of the lens in the ey...

    Text Solution

    |

  11. The ciliary muscles of eye control the curvature of the lens in the ey...

    Text Solution

    |

  12. A parallel beam of light falls on a solid tranparent sphere. Q. W...

    Text Solution

    |

  13. A parallel beam of light falls on a solid tranparent sphere. Q. I...

    Text Solution

    |

  14. A parallel beam of light falls on a solid tranparent sphere. Q. F...

    Text Solution

    |

  15. Pulfrich refractometer is used to measure the refractive index of soli...

    Text Solution

    |

  16. Pulfrich refractometer is used to measure the refractive index of soli...

    Text Solution

    |

  17. Pulfrich refractometer is used to measure the refractive index of soli...

    Text Solution

    |

  18. An object is present on the principal axis of a concave mirror at a di...

    Text Solution

    |

  19. An object is placed between a plane mirror and a concave mirror of foc...

    Text Solution

    |

  20. An object is present on the principal axis of a concave mirror at a di...

    Text Solution

    |