An object kept near a convex lens of focal length f, executes SHM between P and Q according to the equation `y=A sinomegat`, O being the mean position. Take x-axis as the principal axis of the lens and `A lt lt D` to answer the following questions:

Q. The amplitude of oscillation of the image is

Options

A. A
B. 2A
C. `A//2`
D. Image does not oscillate

Answer

c

Explanation

`(1)/(v)-(1)/(-3f)=(1)/(f)rArr(1)/(v)=(1)/(f)-(1)/(3f)rArrv=(3f)/(2)`
`(y_(1))/(y)=(v)/(3f)rArry_(1)=y(v)/(3f)=(y)/(2)`
If `y_(max)=A` then `y_(1 max)=A_(1)=A//2`
Max velocity `=omegaA_(1) =omegaA//2`