An object kept near a convex lens of focal length f, executes SHM between P and Q according to the equation `y=A sinomegat`, O being the mean position. Take x-axis as the principal axis of the lens and `A lt lt D` to answer the following questions:

Q. The velocity of the image when the object crosses the mean position and goes toward Q is

Options

A. `A omega`
B. `-Aomega`
C. `Aomega//2`
D. None of these

Answer

c.

Explanation

`(1)/(v)-(1)/(-3f)=(1)/(f)rArr(1)/(v)=(1)/(f)-(1)/(3f)rArrv=(3f)/(2)`
`(y_(1))/(y)=(v)/(3f)rArry_(1)=y(v)/(3f)=(y)/(2)`
If `y_(max)=A` then `y_(1 max)=A_(1)=A//2`
Max velocity `=omegaA_(1) =omegaA//2`