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A convex lens is in contact with a conc...

A convex lens is in contact with a concave lens. The magnitude of the ration of their focal lengths is `2//3`. Their equivalent focal length is 30cm. What are their individual focal lengths?

A

`-15,10`

B

`-10,15`

C

`75,50`

D

`-75,50`

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The correct Answer is:
To solve the problem, we need to find the individual focal lengths of a convex lens (f1) and a concave lens (f2) that are in contact, given the ratio of their focal lengths and their equivalent focal length. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - The ratio of the focal lengths of the convex lens (f1) and the concave lens (f2) is given as \( \frac{f1}{f2} = \frac{2}{3} \). - The equivalent focal length (F) of the combination is given as \( F = 30 \, \text{cm} \). 2. **Expressing the Focal Lengths in Terms of Each Other**: - From the ratio \( \frac{f1}{f2} = \frac{2}{3} \), we can express \( f2 \) in terms of \( f1 \): \[ f2 = \frac{3}{2} f1 \] 3. **Using the Formula for Equivalent Focal Length**: - For two lenses in contact, the formula for the equivalent focal length is: \[ \frac{1}{F} = \frac{1}{f1} + \frac{1}{f2} \] - Substituting \( f2 \) from the previous step into this equation gives: \[ \frac{1}{30} = \frac{1}{f1} + \frac{1}{\left(\frac{3}{2} f1\right)} \] 4. **Simplifying the Equation**: - The term \( \frac{1}{\left(\frac{3}{2} f1\right)} \) can be rewritten as \( \frac{2}{3 f1} \): \[ \frac{1}{30} = \frac{1}{f1} + \frac{2}{3 f1} \] - Combining the fractions on the right-hand side: \[ \frac{1}{30} = \frac{3 + 2}{3 f1} = \frac{5}{3 f1} \] 5. **Cross-Multiplying to Solve for f1**: - Cross-multiplying gives: \[ 1 \cdot 3 f1 = 30 \cdot 5 \] \[ 3 f1 = 150 \] \[ f1 = \frac{150}{3} = 50 \, \text{cm} \] 6. **Finding f2**: - Now substituting \( f1 \) back into the equation for \( f2 \): \[ f2 = \frac{3}{2} f1 = \frac{3}{2} \cdot 50 = 75 \, \text{cm} \] 7. **Considering the Sign of f2**: - Since f2 is a concave lens, it will be negative: \[ f2 = -75 \, \text{cm} \] ### Final Result: - The individual focal lengths are: - \( f1 = 50 \, \text{cm} \) (Convex lens) - \( f2 = -75 \, \text{cm} \) (Concave lens)

To solve the problem, we need to find the individual focal lengths of a convex lens (f1) and a concave lens (f2) that are in contact, given the ratio of their focal lengths and their equivalent focal length. ### Step-by-Step Solution: 1. **Understanding the Given Information**: - The ratio of the focal lengths of the convex lens (f1) and the concave lens (f2) is given as \( \frac{f1}{f2} = \frac{2}{3} \). - The equivalent focal length (F) of the combination is given as \( F = 30 \, \text{cm} \). ...
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