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Light waves from two coherent sources su...

Light waves from two coherent sources superimpose at a point. The waves, at this point, can be expressed as `y_(1) = a sin [10^(15) pi t]` and `y_(2)a sin [10^(15) pi t + phi]`. Find the resultant amplitude if phase difference `phi` is
(a) zero
(b) `pi//3`
(c) `pi`
Also find the frequency (Hz) of resultant wave in each case.

Text Solution

AI Generated Solution

To find the resultant amplitude and frequency of the superimposed light waves from two coherent sources, we will analyze the given equations step by step. ### Given: 1. \( y_1 = a \sin(10^{15} \pi t) \) 2. \( y_2 = a \sin(10^{15} \pi t + \phi) \) ### Amplitude Calculation: The resultant amplitude \( A \) can be calculated using the formula: ...
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