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Two coherent sources emit light waves wh...

Two coherent sources emit light waves which superimpose at a point where these can be expressed as
`E_(1) = E_(0) sin(omega t + pi//4)`
`E_(2) = 2E_(0) sin(omega t - pi//4)`
Here, `E_(1) and E_(2)` are the electric field strenghts of the two waves at the given point.
If I is the intensity of wave expressed by field strenght `E_(1)`, find the resultant intensity

Text Solution

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To find the resultant intensity of the two coherent light waves given by their electric field strengths \( E_1 \) and \( E_2 \), we can follow these steps: ### Step 1: Identify the Electric Field Strengths We have: \[ E_1 = E_0 \sin(\omega t + \frac{\pi}{4}) \] \[ ...
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