Young's double slit experiment is perfor-med inside water `(mu = 43)` with light of frequency `6 xx 10^(14)` Hz. If the slits are separated by 0.2 mm and the screen kept 1 m from the slits, find the fringe width. Using the same set-up, what will the fringe width be if the experiment is performed in air?

Explanation

To solve the problem of finding the fringe width in Young's double slit experiment performed in water and air, we can follow these steps:

### Step 1: Calculate the wavelength of light in air
We know that the speed of light \( C \) is related to frequency \( f \) and wavelength \( \lambda \) by the equation:
\[ C = f \cdot \lambda \]
Rearranging this gives:
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