Home
Class 12
PHYSICS
In Young's experiment, light of waveleng...

In Young's experiment, light of wavelength 600 nm falls on the double slits separated by 0.1 mm. What is the highest order of maximum intensity in the interference pattern obtained on a screen kept 3 m from the slits? How does the highest order change if the distance of screen from the slits is changed?

Text Solution

AI Generated Solution

To solve the problem of finding the highest order of maximum intensity in Young's double slit experiment, we can follow these steps: ### Step 1: Identify the Given Values We have the following values from the problem: - Wavelength of light (λ) = 600 nm = 600 x 10^-9 m - Distance between the slits (d) = 0.1 mm = 0.1 x 10^-3 m - Distance from the slits to the screen (D) = 3 m ...
Promotional Banner

Topper's Solved these Questions

  • WAVE OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Solved Examples|10 Videos
  • WAVE OPTICS

    CENGAGE PHYSICS ENGLISH|Exercise Exercise 2.1|12 Videos
  • SOURCES OF MAGNETIC FIELD

    CENGAGE PHYSICS ENGLISH|Exercise single correct Ansewer type|12 Videos

Similar Questions

Explore conceptually related problems

In Young's experiment performed with light or wavelength 5500 Å what should be the separation between the two slits so that the highest order of maximum intensity in the interference pattern is 2 ? You may assume D gt gt d.

Two slits 4.0 xx 10^(-6) m apart are illuminated by light of wavelength 600nm . What is the highest order fringe in the interference pattern?

In Young's experiment the slits, separated by d = 0.8 mm , are illuminated with light of wavelength 7200 Å, Interference pattern is obtained on a screen D = 2 m from the slits. Find minimum distance from central maximum at which the a average intensity is 50% if of maximum?

A source emitting light of wavelengths 480 nm and 600 nm is used in a double slit interference experiment. The separation between the slits is 0.25 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths.

In Young.s double slit experiment, blue-green light of wavelength 500nm is used. The slits are 1.20mm apart, and the viewing screen is 5.40 m away from the slits. What is the fringe width.

In Yonung's double-slit experiment, two slits which are separated by 1.2 mm are illuminated with a monochromatic light of wavelength 6000 Å The interference pattern is observed on a screen placed at a distance of 1 m from the slits. Find the number of bright fringes formed over 1 cm width on the screen.

In Young's double-slit experiment, the intensity at a point P on the screen is half the maximum intensity in the interference pattern. If the wavelength of light used is lambda and d is the distance between the slits, the angular separation between point P and the center of the screen is

In a Young's double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to:

In a Young's double slit experiment the separation between the slits is 0.10 mm, the wavelength of light used is 600 mm and the interference pattern is observed on a screen 1.0 m away. Find the separation between the successive bright fringes.

Monochromatic light from a narrow slit illuminates two parallel slits producing an interference pattern on a screen. The separation between the two slits is now doubled and the distance between the screen and the slits is reduced to half. The fringe width