Young's interference experiment is performed with monochromatic light. The separation between the slits is 0.500 mm, and the interference pattern on a screen 3.30 m away shows the first side maximum 3.40 mm form the center of the pattern. What is the wavelength ?

Explanation

To solve the problem, we will use the formula for the position of the interference maxima in Young's double-slit experiment:

\[ Y_n = \frac{n \cdot D \cdot \lambda}{d} \]

Where:
- \( Y_n \) = position of the nth maximum from the center (in meters)
- \( n \) = order of the maximum (1 for the first side maximum)
- \( D \) = distance from the slits to the screen (in meters)
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