The width of one of the two slits in a Young's double slit experiment is double of the other slit. Assuming that the amplitude of the light coming from a slit is proportional to the slit width, find the ratio of the maximum to the minimum intensity in the interference pattern.

Explanation

To solve the problem, we need to find the ratio of the maximum to the minimum intensity in the interference pattern of a Young's double slit experiment where one slit is double the width of the other. Let's break down the solution step by step.

### Step 1: Define the Amplitudes
Let the width of slit 1 be \( D \) and the amplitude of light coming from slit 1 be \( A_1 = a \). Since the width of slit 2 is double that of slit 1, we have:
\[ D_2 = 2D \quad \text{and} \quad A_2 = 2a \]

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