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The de Broglie wavelength of a particel ...

The de Broglie wavelength of a particel of kinetic energy K is `lamda`. What will be the wavelength of the particle, if its kinetic energy is `(K)/(4)` ?

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If `lamda` is the de Broglie wavelength of the particle of kinetic energy K, then
`lamda=(h)/(sqrt(2mK))`
Suppose that the de Broglie wavlength of the particle becomes `lamda^``, when its kinetic energy is `(K)/(4)`, then
`lamda^`=(h)/(sqrt((2mK)/(4)))=2((h)/(sqrt(2mK)))=2lamda`
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