if the cathode and the anode are kept at the same potential, the emitted electrons have

Options

A. the same KE equal to 1.36 eV
B. the average KE equal to `((1.36)/(2))` eV
C. the maximum KE equal to 1.36 eV
D. the minimum KE equal to 1.36 eV

Explanation

To solve the question, "If the cathode and the anode are kept at the same potential, the emitted electrons have," we can follow these steps:

### Step 1: Understand the Photoelectric Effect
The photoelectric effect describes the phenomenon where electrons are emitted from a material (usually a metal) when it is exposed to light (photons) of sufficient energy. The energy of the emitted electrons depends on the energy of the incoming photons and the work function of the material.

**Hint:** Recall that the energy of the incoming photons is given by \( E = h \nu \), where \( h \) is Planck's constant and \( \nu \) is the frequency of the light.

### Step 2: Apply Einstein's Photoelectric Equation
Einstein's photoelectric equation can be expressed as:
\[ K.E. = h \nu - W \]
where:
- \( K.E. \) is the kinetic energy of the emitted electrons,
- \( h \nu \) is the energy of the incident photons,
- \( W \) is the work function of the material (the minimum energy required to remove an electron from the surface).

**Hint:** The work function \( W \) is a characteristic property of the material and is essential for determining if electrons will be emitted.

### Step 3: Analyze the Situation with Equal Potential
When the cathode and anode are kept at the same potential, there is no potential difference between them. This means that the electric field between the cathode and anode is zero. As a result, the emitted electrons do not experience any force due to an electric field.

**Hint:** Consider what happens to the motion of the electrons when there is no electric field acting on them.

### Step 4: Determine the Kinetic Energy of the Emitted Electrons
Since the electrons are emitted due to the energy provided by the photons, their maximum kinetic energy can be expressed as:
\[ K.E. = h \nu - W \]
However, since there is no electric field to accelerate the electrons towards the anode, they will not gain any additional kinetic energy from the electric field.

**Hint:** Remember that the kinetic energy of the emitted electrons is still determined by the energy of the photons minus the work function, but they will not gain energy from the electric field.

### Step 5: Conclusion
Thus, if the cathode and anode are kept at the same potential, the emitted electrons will have a kinetic energy equal to \( K.E. = h \nu - W \), but they will not be accelerated towards the anode due to the absence of an electric field.

**Final Answer:** The emitted electrons have a kinetic energy of \( K.E. = h \nu - W \), but they will not be accelerated towards the anode.