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The ratio of momenta of an electron and ...

The ratio of momenta of an electron and an `alpha`-particle which are accelerated from rest by a potential difference of 100 V is

A

1

B

`sqrt((2m_e)/(m_alpha))`

C

`sqrt((m_e)/(m_alpha))`

D

`sqrt((m_e)/(2m_alpha))`

Text Solution

Verified by Experts

The correct Answer is:
D

`lamda=(h)/(sqrt(meV)`
`p=sqrt(2meV)`
`(p_e)/(p_alpha)=sqrt((2m_eeV)/(2m_alpha(2e)V))`
`(p_e)/(p_alpha)=sqrt((m_e)/(2m_alpha))`
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