The energy of a photon is equal to the kinetic energy of a
proton. The energy of the photon is E. Let `lambda_1`be the de-Broglie wavelength of the
proton and `lambda_2` be the wavelength of the photon. The ratio `(lambda_1)/(lambda_2)` is proportional to
(a)`E^0` (b) `E^(1//2)` (c ) `E^(-1)` (d)`E^(-2)`

Options

A. `E^0`
B. `E^(1)/(2)`
C. `E^-1`
D. `E^-2`

Answer

B

Explanation

`lamda_1=(h)/(p)=(h)/(sqrt(2mE))`
`lamda_2=(hc)/(E)=E^((1)/(2))`