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The radius of seocnd orbit of an electro...

The radius of seocnd orbit of an electron in hydrogen atom is `2.116 eV Å` The de-Broglie wavlength associated with this electron in this orbit would at t=25 s is

A

`6.64A`

B

`1.058A`

C

`2.116A`

D

`13.28A`

Text Solution

Verified by Experts

The correct Answer is:
A
`mvr=n(h)/(2pi)`
`=2((h)/(2pi))` `(n=2)`
or `mvr=(h)/(pi)`
`lamda=(h)/(mv)=` deBroglie wavelength
`=pir=(3.14)(2.116A)=6.64A`
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